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Does going to university in a different country affect your mental health? A Japanese international university surveyed its students in 2018 and published a study the following year that was approved by several ethical and regulatory boards.

The study found that international students have a higher risk of mental health difficulties than the general population. Explore the students data using PostgreSQL to find out if this is true and see if the length of stay is a contributing factor.

Here is a data description of the fields you may find helpful. The full dataset is in one table with 50 fields and, according to the survey, 268 records. Each row is a student.

Field NameDescription
inter_domTypes of students
japanese_cateJapanese language proficiency
english_cateEnglish language proficiency
academicCurrent academic level
ageCurrent age of student
stayCurrent length of stay in years
todepTotal score of depression (PHQ-9 test)
toscTotal score of social connectedness (SCS test)
toasTotal score of Acculturative Stress (ASISS test)

Your task will be to do the following exploratory analysis:

  • Count the number of all records, and all records per student type
  • Filter the data to see how it differs between the student types
  • Find the summary statistics of the diagnostic tests for all students
  • Summarize the data for international students
  • See if length of stay impacts the test scores
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DataFrameas
df
variable
-- Start coding here...
SELECT *
FROM students;
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DataFrameas
df
variable
--NUMBER OF ALL RECORDS
SELECT COUNT(*) AS num_of_records
FROM students; 
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DataFrameas
df
variable
--NUMBER OF RECORDS PER STUDENT TYPE
SELECT inter_dom AS student_type, 
       COUNT(*) AS count_per_student_type
FROM students
WHERE (inter_dom IS NOT NULL) AND (inter_dom <> '')
GROUP BY inter_dom
ORDER BY count_per_student_type DESC;
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DataFrameas
df
variable
WITH avg_scores AS (SELECT age, ROUND(AVG(todep),1) AS avg_depresion_score, ROUND(AVG(tosc),1) AS avg_social_connectedness_score 
FROM students
WHERE age IS NOT NULL
GROUP BY age)

SELECT age, avg_depresion_score, RANK() OVER(ORDER BY avg_depresion_score DESC) AS rank
FROM avg_scores
ORDER BY avg_depresion_score DESC;