如何在 Python 中求一个数的平方：基础与高级方法

print(6 ** 2)

# Expected output: 36技术支持

# Define the number to be squared
number = 6

# Use the ** operator to square the number
squared_number = number ** 2

# Print the result
print(f"The square of {number} is {squared_number}")

# Expected output: The square of 6 is 36技术支持

# Squaring a number using multiplication
number = 6

# Using multiplication operator
squared = number * number  

print(squared)

# Expected output: 36技术支持

# Squaring a number using the pow() function
number = 6

# The first argument is the number, and the second argument is the exponent
squared = pow(number, 2)

print(squared)

# Expected output: 36技术支持

# Squaring a number using the pow() function
number = 6

# Squaring a number with modulo using the pow() function
mod_squared = pow(number, 2, 7)

print(mod_squared)

# Expected output: 1技术支持

# Import the math module
import math

# Squaring a number using math.pow()
number = 5
squared = math.pow(number, 2)

print(squared)

# Expected output: 25.0技术支持

# Import the numpy library with the alias np
import numpy as np

# Squaring a number using NumPy
number = np.array([5])
squared = np.square(number)

print(squared)

# Expected output: [25]技术支持

# Squaring a list of numbers using list comprehension
numbers = [1, 2, 3, 4, 5]
squared = [n ** 2 for n in numbers]

print(squared)
# Expected output: [1, 4, 9, 16, 25]技术支持

# Squaring multiple numbers using a while loop
numbers = [1, 2, 3, 4, 5]
squared_results = []
i = 0

while i < len(numbers):
    squared_results.append(numbers[i] ** 2)
    i += 1

print(squared_results)

# Expected output: [1, 4, 9, 16, 25]技术支持

number = 5

# Bitwise squaring works cleanly only for powers of 2.
# For general integer squaring, the most practical bitwise approach
# is using Python's built-in multiplication at the bit level:
squared = number * number

# For demonstration, here's how left-shift works for a power of 2:
# Squaring 4 (which is 2^2): shift left by 2 positions
power_of_two = 4
squared_pow2 = power_of_two << 2  # 4 * 4 = 16
print(squared_pow2)

# Expected output: 16技术支持

# Store the number in a variable
number = 5

# Original 'number' remains unchanged
squared = number * number 

print(squared)

# Expected output: 25技术支持

# Importing the math module for mathematical functions
import math  

# Attempting to convert the input to float and square it
try:    
	number = 'five'     
	squared = math.pow(float(number), 2)      
	print(squared)
except ValueError as e:    
	# Catching and handling the ValueError that occurs when conversion to float fails    
	print(f"Invalid input: {e}")

# Expected output:
# Invalid input: could not convert string to float: 'five'技术支持